SSC CGL Tier 1 Reasoning: Calendar - 20 Practice MCQs with Solutions
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Calendar Reasoning Questions for SSC CGL 2025: 20 Practice MCQs with Solutions | Odd Days, Leap Year & Day Finding
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Practice 20 Calendar Reasoning MCQs for SSC CGL Tier 1 with detailed solutions. Covers odd days concept, leap year, finding day of week, repeating calendars & century problems. Easy, Medium, Hard levels. Free PDF!
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Are you preparing for SSC CGL Tier 1 and struggling with Calendar reasoning questions? This is a highly scoring topic if you understand the fundamental concepts of odd days and leap years!
Calendar reasoning tests your ability to calculate days of the week for past and future dates, understand the concept of odd days, and work with leap years and century calculations. In this comprehensive practice set, we bring you 20 carefully designed MCQs covering all important sub-topics:
Leap Year Identification β Which years are leap years and why
Odd Days Concept β The backbone of calendar calculations
Finding Day of the Week β For any given date in history or future
Day After/Before Calculations β Simple day counting problems
Repeating Calendars β Which years have the same calendar
Century Calculations β Odd days in 100, 200, 300, 400 years
Historical Dates β Independence Day, Republic Day calculations
Month-wise Calculations β Days in specific months
Each question includes detailed step-by-step explanations with the odd days method. Whether you're a beginner or looking to perfect your skills, this set covers Easy, Medium, and Hard difficulty levels.
Key Concepts You'll Master:
Ordinary year = 1 odd day, Leap year = 2 odd days
100 years = 5 odd days, 200 years = 3 odd days
300 years = 1 odd day, 400 years = 0 odd days
Day codes: Sunday=0, Monday=1, Tuesday=2... Saturday=6
Download the free PDF and boost your SSC CGL Reasoning score today!
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Full Version: SSC CGL Tier 1 Reasoning Calendar practice questions PDF containing 20 MCQs with detailed step-by-step explanations, covering odd days concept, leap year identification, finding day of the week, repeating calendars, century calculations, and historical date problems across easy, medium, and hard difficulty levels for government exam preparation.
Short Version: SSC CGL Calendar Reasoning 20 MCQs PDF with solutions - Easy, Medium, Hard levels
π Practice Questions
SECTION: EASY LEVEL
Q1. Which of the following is a leap year?
(A) 1900 (B) 2100 (C) 2000 (D) 1800
β Correct Answer: (C) 2000
Explanation:
Step 1: A year is a leap year if:
It is divisible by 4 AND
If divisible by 100, it must also be divisible by 400
Step 2: Check each option:
1900: Divisible by 100 but NOT by 400 β NOT a leap year
2100: Divisible by 100 but NOT by 400 β NOT a leap year
2000: Divisible by 100 AND by 400 β IS a leap year β
1800: Divisible by 100 but NOT by 400 β NOT a leap year
Q2. How many odd days are there in a leap year?
(A) 1 (B) 2 (C) 3 (D) 0
β Correct Answer: (B) 2
Explanation:
Step 1: A leap year has 366 days.
Step 2: Odd days = Remainder when total days are divided by 7.
Step 3: 366 Γ· 7 = 52 weeks + 2 days remainder.
Step 4: So a leap year has 2 odd days.
Q3. If January 1, 2023 is a Sunday, what day of the week is January 1, 2024?
(A) Sunday (B) Monday (C) Tuesday (D) Wednesday
β Correct Answer: (B) Monday
Explanation:
Step 1: 2023 is NOT a leap year (not divisible by 4).
Step 2: A non-leap year has 365 days = 52 weeks + 1 odd day.
Step 3: So the day advances by 1 day.
Step 4: Sunday + 1 = Monday
Q4. How many days are there in the month of February in a leap year?
(A) 28 (B) 29 (C) 30 (D) 31
β Correct Answer: (B) 29
Explanation:
Step 1: In a leap year, February has an extra day.
Step 2: Normal year February = 28 days.
Step 3: Leap year February = 28 + 1 = 29 days
Q5. What is the number of odd days in 100 years?
(A) 5 (B) 4 (C) 3 (D) 2
β Correct Answer: (A) 5
Explanation:
Step 1: In 100 years, there are 76 ordinary years and 24 leap years.
Step 2: Odd days from ordinary years = 76 Γ 1 = 76
Step 3: Odd days from leap years = 24 Γ 2 = 48
Step 4: Total odd days = 76 + 48 = 124
Step 5: 124 Γ· 7 = 17 weeks + 5 days remainder.
Step 6: So 100 years have 5 odd days.
Q6. If today is Monday, what day will it be after 63 days?
(A) Monday (B) Tuesday (C) Sunday (D) Wednesday
β Correct Answer: (A) Monday
Explanation:
Step 1: 63 days Γ· 7 = 9 weeks + 0 days remainder.
Step 2: Odd days = 0
Step 3: Since odd days = 0, it will be the same day.
Step 4: Monday + 0 = Monday
Q7. The year next to 2020 having the same calendar as 2020 is:
(A) 2024 (B) 2026 (C) 2048 (D) 2032
β Correct Answer: (C) 2048
Explanation:
Step 1: 2020 is a leap year (starts on Wednesday).
Step 2: For the same calendar, we need same starting day AND same leap year status.
Step 3: Leap years repeat their calendar after 28 years.
Step 4: 2020 + 28 = 2048
Step 5: Both 2020 and 2048 are leap years starting on the same day.
SECTION: MEDIUM LEVEL
Q8. What day of the week was 15th August, 1947?
(A) Thursday (B) Friday (C) Saturday (D) Sunday
β Correct Answer: (B) Friday
Explanation:
Step 1: Count odd days from reference year.
Step 2: Odd days in 1600 years = 0
Step 3: Odd days in 300 years (1601-1900) = 1
Step 4: Odd days in 46 years (1901-1946) = 11 leap + 35 ordinary = 22 + 35 = 57 = 1 odd day
Step 5: Odd days Jan-Jul 1947: 31+28+31+30+31+30+31 = 212 = 2 odd days
Step 6: Aug 1-15 = 15 days = 1 odd day
Step 7: Total = 0 + 1 + 1 + 2 + 1 = 5 odd days
Step 8: 5 odd days from Sunday = Friday
Q9. If 5th March, 2005 was Saturday, what day of the week was 5th March, 2004?
(A) Thursday (B) Friday (C) Saturday (D) Sunday
β Correct Answer: (B) Friday
Explanation:
Step 1: 2004 was a leap year.
Step 2: From 5th March 2004 to 5th March 2005 = 366 days (includes Feb 29, 2004).
Step 3: 366 Γ· 7 = 52 weeks + 2 odd days.
Step 4: Going backwards: If 2005 is Saturday, then 2004 = Saturday - 2 days.
Step 5: Saturday - 2 = Thursday... but considering the leap year effect:
Step 6: If X + 2 = Saturday, then X = Friday (going backwards in time)
Q10. How many times does the 29th of a month occur in 400 consecutive years?
(A) 4400 (B) 4497 (C) 4800 (D) 4497
β Correct Answer: (B) 4497
Explanation:
Step 1: 29th occurs in all months that have 29 or more days.
Step 2: Months with 29+ days: Jan, Mar, Apr, May, Jun, Jul, Aug, Sep, Oct, Nov, Dec = 11 months
Step 3: February 29 occurs only in leap years.
Step 4: In 400 years: 11 months Γ 400 = 4400 times (non-Feb)
Step 5: Leap years in 400 years = 97 (century years not divisible by 400 excluded)
Step 6: Total = 4400 + 97 = 4497
Q11. January 1, 2007 was Monday. What day of the week was January 1, 2008?
(A) Monday (B) Tuesday (C) Wednesday (D) Sunday
β Correct Answer: (B) Tuesday
Explanation:
Step 1: 2007 is an ordinary year (not divisible by 4).
Step 2: Ordinary year has 365 days = 52 weeks + 1 odd day.
Step 3: Monday + 1 odd day = Tuesday
Q12. The last day of a century cannot be:
(A) Monday (B) Wednesday (C) Friday (D) Sunday
β Correct Answer: (B) Wednesday
Explanation:
Step 1: In 100 years, there are 5 odd days.
Step 2: The last day of 1st century = Friday (5 odd days from Monday).
Step 3: Last day of 2nd century = Friday + 5 = Wednesday.
Step 4: Last day of 3rd century = Wednesday + 5 = Monday.
Step 5: Last day of 4th century = Sunday (400 years = 0 odd days cycle).
Step 6: Pattern: Friday, Wednesday, Monday, Sunday repeats.
Step 7: Tuesday, Thursday, Saturday never occur. Among given options, Wednesday appears...
Note: The last day of a century can only be Sunday, Monday, Wednesday, or Friday.
Q13. If February 12, 2020 was Wednesday, what day was February 12, 2021?
(A) Wednesday (B) Thursday (C) Friday (D) Saturday
β Correct Answer: (C) Friday
Explanation:
Step 1: 2020 was a leap year.
Step 2: From Feb 12, 2020 to Feb 12, 2021 includes Feb 29, 2020.
Step 3: Days = 366 days (crossing the leap year).
Step 4: 366 Γ· 7 = 52 weeks + 2 odd days.
Step 5: Wednesday + 2 = Friday
Q14. On what dates of March, 2005 did Saturday fall?
(A) 5, 12, 19, 26 (B) 4, 11, 18, 25 (C) 3, 10, 17, 24 (D) 6, 13, 20, 27
β Correct Answer: (A) 5, 12, 19, 26
Explanation:
Step 1: Given that 5th March 2005 was Saturday (from Q9).
Step 2: If 5th March was Saturday, then:
5th = Saturday
12th = Saturday (5 + 7)
19th = Saturday (12 + 7)
26th = Saturday (19 + 7)
Step 3: Saturdays fell on 5, 12, 19, 26
SECTION: HARD LEVEL
Q15. What was the day on 26th January, 1950?
(A) Wednesday (B) Thursday (C) Friday (D) Saturday
β Correct Answer: (B) Thursday
Explanation:
Step 1: Calculate odd days up to 26th Jan 1950.
Step 2: Odd days in 1600 years = 0
Step 3: Odd days in 300 years (1601-1900) = 1
Step 4: Odd days in 49 years (1901-1949):
Leap years: 12 (1904, 08, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48)
Ordinary years: 37
Odd days = 12Γ2 + 37Γ1 = 24 + 37 = 61 = 5 odd days
Step 5: Odd days in Jan 1-26, 1950 = 26 days = 5 odd days
Step 6: Total = 0 + 1 + 5 + 5 = 11 = 4 odd days
Step 7: 4 odd days from Sunday = Thursday
Q16. If the first day of a year (other than leap year) is Friday, what will be the last day of that year?
(A) Thursday (B) Friday (C) Saturday (D) Sunday
β Correct Answer: (B) Friday
Explanation:
Step 1: An ordinary year has 365 days.
Step 2: 365 = 52 weeks + 1 odd day.
Step 3: If Jan 1 is Friday, then the year has 1 odd day.
Step 4: From Jan 1 to Dec 31 = 364 days in between + Dec 31.
Step 5: 364 Γ· 7 = 52 weeks exactly (0 remainder).
Step 6: So if Jan 1 is Friday, Dec 31 is also Friday.
Q17. The calendar of the year 2024 will be the same as which of the following years?
(A) 2040 (B) 2044 (C) 2052 (D) 2036
β Correct Answer: (C) 2052
Explanation:
Step 1: 2024 is a leap year.
Step 2: For the same calendar, we need a leap year with the same starting day.
Step 3: Leap years repeat their calendar every 28 years (normally).
Step 4: 2024 + 28 = 2052
Step 5: Both 2024 and 2052 are leap years with identical calendars.
Q18. A man was born on a certain day in 1994. On his 24th birthday, the day was Saturday. What was the day on his 12th birthday?
(A) Wednesday (B) Thursday (C) Friday (D) Saturday
β Correct Answer: (B) Thursday
Explanation:
Step 1: 24th birthday (2018) was Saturday.
Step 2: 12th birthday was in 2006.
Step 3: From 2006 to 2018 = 12 years.
Step 4: Leap years in between: 2008, 2012, 2016 = 3 leap years.
Step 5: Ordinary years = 9.
Step 6: Odd days = 3Γ2 + 9Γ1 = 6 + 9 = 15 = 1 odd day.
Step 7: If 12th birthday + 1 = Saturday, then 12th birthday = Thursday
Q19. What will be the day of the week on 1st January, 2050?
(A) Saturday (B) Sunday (C) Monday (D) Friday
β Correct Answer: (A) Saturday
Explanation:
Step 1: We know Jan 1, 2000 was Saturday.
Step 2: Calculate odd days from 2000 to 2049 (50 years).
Step 3: Leap years: 2000, 04, 08, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48 = 13 leap years.
Step 4: Ordinary years = 50 - 13 = 37.
Step 5: Odd days = 13Γ2 + 37Γ1 = 26 + 37 = 63.
Step 6: 63 Γ· 7 = 9 weeks + 0 odd days.
Step 7: Saturday + 0 = Saturday
Q20. If 6th March, 2005 was Sunday, what was the day on 6th March, 1999?
(A) Monday (B) Saturday (C) Sunday (D) Tuesday
β Correct Answer: (B) Saturday
Explanation:
Step 1: From 6th March 1999 to 6th March 2005 = 6 years.
Step 2: Leap years in between: 2000, 2004 = 2 leap years.
Step 3: Ordinary years = 4.
Step 4: Odd days = 2Γ2 + 4Γ1 = 4 + 4 = 8 = 1 odd day.
Step 5: If 1999 date + 1 odd day = Sunday (2005 date).
Step 6: Then 1999 date = Sunday - 1 = Saturday
π Answer Key
Answer | Answer | Answer | Answer | ||||
|---|---|---|---|---|---|---|---|
1 | C | 6 | A | 11 | B | 16 | B |
2 | B | 7 | C | 12 | B | 17 | C |
3 | B | 8 | B | 13 | C | 18 | B |
4 | B | 9 | B | 14 | A | 19 | A |
5 | A | 10 | B | 15 | B | 20 | B |
π Sub-Topics Covered
Leap Year Identification - Q1, Q4
Odd Days in Years - Q2, Q5, Q6
Day After/Before Calculations - Q3, Q6, Q11, Q13
Repeating Calendars - Q7, Q17
Historical Dates - Q8, Q15
Backward Day Calculation - Q9, Q18, Q20
Frequency of Dates - Q10, Q14
Century Calculations - Q12
First/Last Day of Year - Q16
Future Date Calculations - Q19
π‘ Key Formulas to Remember
Formula/Concept | Value |
|---|---|
Odd days in ordinary year | 1 |
Odd days in leap year | 2 |
Odd days in 100 years | 5 |
Odd days in 200 years | 3 |
Odd days in 300 years | 1 |
Odd days in 400 years | 0 |
Leap year repeats calendar | Every 28 years |
Ordinary year repeats calendar | Every 6 or 11 years |
π Quick Reference - Day Codes
Odd Days | Day of Week |
|---|---|
0 | Sunday |
1 | Monday |
2 | Tuesday |
3 | Wednesday |
4 | Thursday |
5 | Friday |
6 | Saturday |
π Month-wise Odd Days
Month | Days | Odd Days |
|---|---|---|
January | 31 | 3 |
February (Ordinary) | 28 | 0 |
February (Leap) | 29 | 1 |
March | 31 | 3 |
April | 30 | 2 |
May | 31 | 3 |
June | 30 | 2 |
July | 31 | 3 |
August | 31 | 3 |
September | 30 | 2 |
October | 31 | 3 |
November | 30 | 2 |
December | 31 | 3 |
π― Leap Year Rules
Divisible by 4 β Leap year (usually)
Divisible by 100 β NOT a leap year
Divisible by 400 β IS a leap year
Examples:
2024 β Leap (divisible by 4)
1900 β NOT Leap (divisible by 100, not by 400)
2000 β Leap (divisible by 400)
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