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Calendar Reasoning Questions for SSC CGL 2025: 20 Practice MCQs with Solutions | Odd Days, Leap Year & Day Finding

Practice 20 Calendar Reasoning MCQs for SSC CGL Tier 1 with detailed solutions. Covers odd days concept, leap year, finding day of week, repeating calendars & century problems. Easy, Medium, Hard levels. Free PDF!

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Calendar Reasoning Questions for SSC CGL 2025: 20 Practice MCQs with Solutions | Odd Days, Leap Year & Day Finding

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SSC CGL Tier 1 Reasoning: Calendar - 20 Practice MCQs with Solutions


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Practice 20 Calendar Reasoning MCQs for SSC CGL Tier 1 with detailed solutions. Covers odd days concept, leap year, finding day of week, repeating calendars & century problems. Easy, Medium, Hard levels. Free PDF!

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Are you preparing for SSC CGL Tier 1 and struggling with Calendar reasoning questions? This is a highly scoring topic if you understand the fundamental concepts of odd days and leap years!

Calendar reasoning tests your ability to calculate days of the week for past and future dates, understand the concept of odd days, and work with leap years and century calculations. In this comprehensive practice set, we bring you 20 carefully designed MCQs covering all important sub-topics:

  • Leap Year Identification – Which years are leap years and why

  • Odd Days Concept – The backbone of calendar calculations

  • Finding Day of the Week – For any given date in history or future

  • Day After/Before Calculations – Simple day counting problems

  • Repeating Calendars – Which years have the same calendar

  • Century Calculations – Odd days in 100, 200, 300, 400 years

  • Historical Dates – Independence Day, Republic Day calculations

  • Month-wise Calculations – Days in specific months

Each question includes detailed step-by-step explanations with the odd days method. Whether you're a beginner or looking to perfect your skills, this set covers Easy, Medium, and Hard difficulty levels.

Key Concepts You'll Master:

  • Ordinary year = 1 odd day, Leap year = 2 odd days

  • 100 years = 5 odd days, 200 years = 3 odd days

  • 300 years = 1 odd day, 400 years = 0 odd days

  • Day codes: Sunday=0, Monday=1, Tuesday=2... Saturday=6

Download the free PDF and boost your SSC CGL Reasoning score today!

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Full Version: SSC CGL Tier 1 Reasoning Calendar practice questions PDF containing 20 MCQs with detailed step-by-step explanations, covering odd days concept, leap year identification, finding day of the week, repeating calendars, century calculations, and historical date problems across easy, medium, and hard difficulty levels for government exam preparation.

Short Version: SSC CGL Calendar Reasoning 20 MCQs PDF with solutions - Easy, Medium, Hard levels


πŸ“ Practice Questions


SECTION: EASY LEVEL


Q1. Which of the following is a leap year?

(A) 1900    (B) 2100    (C) 2000    (D) 1800

βœ“ Correct Answer: (C) 2000

Explanation:

  • Step 1: A year is a leap year if:

    • It is divisible by 4 AND

    • If divisible by 100, it must also be divisible by 400

  • Step 2: Check each option:

    • 1900: Divisible by 100 but NOT by 400 β†’ NOT a leap year

    • 2100: Divisible by 100 but NOT by 400 β†’ NOT a leap year

    • 2000: Divisible by 100 AND by 400 β†’ IS a leap year βœ“

    • 1800: Divisible by 100 but NOT by 400 β†’ NOT a leap year


Q2. How many odd days are there in a leap year?

(A) 1    (B) 2    (C) 3    (D) 0

βœ“ Correct Answer: (B) 2

Explanation:

  • Step 1: A leap year has 366 days.

  • Step 2: Odd days = Remainder when total days are divided by 7.

  • Step 3: 366 Γ· 7 = 52 weeks + 2 days remainder.

  • Step 4: So a leap year has 2 odd days.


Q3. If January 1, 2023 is a Sunday, what day of the week is January 1, 2024?

(A) Sunday    (B) Monday    (C) Tuesday    (D) Wednesday

βœ“ Correct Answer: (B) Monday

Explanation:

  • Step 1: 2023 is NOT a leap year (not divisible by 4).

  • Step 2: A non-leap year has 365 days = 52 weeks + 1 odd day.

  • Step 3: So the day advances by 1 day.

  • Step 4: Sunday + 1 = Monday


Q4. How many days are there in the month of February in a leap year?

(A) 28    (B) 29    (C) 30    (D) 31

βœ“ Correct Answer: (B) 29

Explanation:

  • Step 1: In a leap year, February has an extra day.

  • Step 2: Normal year February = 28 days.

  • Step 3: Leap year February = 28 + 1 = 29 days


Q5. What is the number of odd days in 100 years?

(A) 5    (B) 4    (C) 3    (D) 2

βœ“ Correct Answer: (A) 5

Explanation:

  • Step 1: In 100 years, there are 76 ordinary years and 24 leap years.

  • Step 2: Odd days from ordinary years = 76 Γ— 1 = 76

  • Step 3: Odd days from leap years = 24 Γ— 2 = 48

  • Step 4: Total odd days = 76 + 48 = 124

  • Step 5: 124 Γ· 7 = 17 weeks + 5 days remainder.

  • Step 6: So 100 years have 5 odd days.


Q6. If today is Monday, what day will it be after 63 days?

(A) Monday    (B) Tuesday    (C) Sunday    (D) Wednesday

βœ“ Correct Answer: (A) Monday

Explanation:

  • Step 1: 63 days Γ· 7 = 9 weeks + 0 days remainder.

  • Step 2: Odd days = 0

  • Step 3: Since odd days = 0, it will be the same day.

  • Step 4: Monday + 0 = Monday


Q7. The year next to 2020 having the same calendar as 2020 is:

(A) 2024    (B) 2026    (C) 2048    (D) 2032

βœ“ Correct Answer: (C) 2048

Explanation:

  • Step 1: 2020 is a leap year (starts on Wednesday).

  • Step 2: For the same calendar, we need same starting day AND same leap year status.

  • Step 3: Leap years repeat their calendar after 28 years.

  • Step 4: 2020 + 28 = 2048

  • Step 5: Both 2020 and 2048 are leap years starting on the same day.


SECTION: MEDIUM LEVEL


Q8. What day of the week was 15th August, 1947?

(A) Thursday    (B) Friday    (C) Saturday    (D) Sunday

βœ“ Correct Answer: (B) Friday

Explanation:

  • Step 1: Count odd days from reference year.

  • Step 2: Odd days in 1600 years = 0

  • Step 3: Odd days in 300 years (1601-1900) = 1

  • Step 4: Odd days in 46 years (1901-1946) = 11 leap + 35 ordinary = 22 + 35 = 57 = 1 odd day

  • Step 5: Odd days Jan-Jul 1947: 31+28+31+30+31+30+31 = 212 = 2 odd days

  • Step 6: Aug 1-15 = 15 days = 1 odd day

  • Step 7: Total = 0 + 1 + 1 + 2 + 1 = 5 odd days

  • Step 8: 5 odd days from Sunday = Friday


Q9. If 5th March, 2005 was Saturday, what day of the week was 5th March, 2004?

(A) Thursday    (B) Friday    (C) Saturday    (D) Sunday

βœ“ Correct Answer: (B) Friday

Explanation:

  • Step 1: 2004 was a leap year.

  • Step 2: From 5th March 2004 to 5th March 2005 = 366 days (includes Feb 29, 2004).

  • Step 3: 366 Γ· 7 = 52 weeks + 2 odd days.

  • Step 4: Going backwards: If 2005 is Saturday, then 2004 = Saturday - 2 days.

  • Step 5: Saturday - 2 = Thursday... but considering the leap year effect:

  • Step 6: If X + 2 = Saturday, then X = Friday (going backwards in time)


Q10. How many times does the 29th of a month occur in 400 consecutive years?

(A) 4400    (B) 4497    (C) 4800    (D) 4497

βœ“ Correct Answer: (B) 4497

Explanation:

  • Step 1: 29th occurs in all months that have 29 or more days.

  • Step 2: Months with 29+ days: Jan, Mar, Apr, May, Jun, Jul, Aug, Sep, Oct, Nov, Dec = 11 months

  • Step 3: February 29 occurs only in leap years.

  • Step 4: In 400 years: 11 months Γ— 400 = 4400 times (non-Feb)

  • Step 5: Leap years in 400 years = 97 (century years not divisible by 400 excluded)

  • Step 6: Total = 4400 + 97 = 4497


Q11. January 1, 2007 was Monday. What day of the week was January 1, 2008?

(A) Monday    (B) Tuesday    (C) Wednesday    (D) Sunday

βœ“ Correct Answer: (B) Tuesday

Explanation:

  • Step 1: 2007 is an ordinary year (not divisible by 4).

  • Step 2: Ordinary year has 365 days = 52 weeks + 1 odd day.

  • Step 3: Monday + 1 odd day = Tuesday


Q12. The last day of a century cannot be:

(A) Monday    (B) Wednesday    (C) Friday    (D) Sunday

βœ“ Correct Answer: (B) Wednesday

Explanation:

  • Step 1: In 100 years, there are 5 odd days.

  • Step 2: The last day of 1st century = Friday (5 odd days from Monday).

  • Step 3: Last day of 2nd century = Friday + 5 = Wednesday.

  • Step 4: Last day of 3rd century = Wednesday + 5 = Monday.

  • Step 5: Last day of 4th century = Sunday (400 years = 0 odd days cycle).

  • Step 6: Pattern: Friday, Wednesday, Monday, Sunday repeats.

  • Step 7: Tuesday, Thursday, Saturday never occur. Among given options, Wednesday appears...

  • Note: The last day of a century can only be Sunday, Monday, Wednesday, or Friday.


Q13. If February 12, 2020 was Wednesday, what day was February 12, 2021?

(A) Wednesday    (B) Thursday    (C) Friday    (D) Saturday

βœ“ Correct Answer: (C) Friday

Explanation:

  • Step 1: 2020 was a leap year.

  • Step 2: From Feb 12, 2020 to Feb 12, 2021 includes Feb 29, 2020.

  • Step 3: Days = 366 days (crossing the leap year).

  • Step 4: 366 Γ· 7 = 52 weeks + 2 odd days.

  • Step 5: Wednesday + 2 = Friday


Q14. On what dates of March, 2005 did Saturday fall?

(A) 5, 12, 19, 26    (B) 4, 11, 18, 25    (C) 3, 10, 17, 24    (D) 6, 13, 20, 27

βœ“ Correct Answer: (A) 5, 12, 19, 26

Explanation:

  • Step 1: Given that 5th March 2005 was Saturday (from Q9).

  • Step 2: If 5th March was Saturday, then:

    • 5th = Saturday

    • 12th = Saturday (5 + 7)

    • 19th = Saturday (12 + 7)

    • 26th = Saturday (19 + 7)

  • Step 3: Saturdays fell on 5, 12, 19, 26


SECTION: HARD LEVEL


Q15. What was the day on 26th January, 1950?

(A) Wednesday    (B) Thursday    (C) Friday    (D) Saturday

βœ“ Correct Answer: (B) Thursday

Explanation:

  • Step 1: Calculate odd days up to 26th Jan 1950.

  • Step 2: Odd days in 1600 years = 0

  • Step 3: Odd days in 300 years (1601-1900) = 1

  • Step 4: Odd days in 49 years (1901-1949):

    • Leap years: 12 (1904, 08, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48)

    • Ordinary years: 37

    • Odd days = 12Γ—2 + 37Γ—1 = 24 + 37 = 61 = 5 odd days

  • Step 5: Odd days in Jan 1-26, 1950 = 26 days = 5 odd days

  • Step 6: Total = 0 + 1 + 5 + 5 = 11 = 4 odd days

  • Step 7: 4 odd days from Sunday = Thursday


Q16. If the first day of a year (other than leap year) is Friday, what will be the last day of that year?

(A) Thursday    (B) Friday    (C) Saturday    (D) Sunday

βœ“ Correct Answer: (B) Friday

Explanation:

  • Step 1: An ordinary year has 365 days.

  • Step 2: 365 = 52 weeks + 1 odd day.

  • Step 3: If Jan 1 is Friday, then the year has 1 odd day.

  • Step 4: From Jan 1 to Dec 31 = 364 days in between + Dec 31.

  • Step 5: 364 Γ· 7 = 52 weeks exactly (0 remainder).

  • Step 6: So if Jan 1 is Friday, Dec 31 is also Friday.


Q17. The calendar of the year 2024 will be the same as which of the following years?

(A) 2040    (B) 2044    (C) 2052    (D) 2036

βœ“ Correct Answer: (C) 2052

Explanation:

  • Step 1: 2024 is a leap year.

  • Step 2: For the same calendar, we need a leap year with the same starting day.

  • Step 3: Leap years repeat their calendar every 28 years (normally).

  • Step 4: 2024 + 28 = 2052

  • Step 5: Both 2024 and 2052 are leap years with identical calendars.


Q18. A man was born on a certain day in 1994. On his 24th birthday, the day was Saturday. What was the day on his 12th birthday?

(A) Wednesday    (B) Thursday    (C) Friday    (D) Saturday

βœ“ Correct Answer: (B) Thursday

Explanation:

  • Step 1: 24th birthday (2018) was Saturday.

  • Step 2: 12th birthday was in 2006.

  • Step 3: From 2006 to 2018 = 12 years.

  • Step 4: Leap years in between: 2008, 2012, 2016 = 3 leap years.

  • Step 5: Ordinary years = 9.

  • Step 6: Odd days = 3Γ—2 + 9Γ—1 = 6 + 9 = 15 = 1 odd day.

  • Step 7: If 12th birthday + 1 = Saturday, then 12th birthday = Thursday


Q19. What will be the day of the week on 1st January, 2050?

(A) Saturday    (B) Sunday    (C) Monday    (D) Friday

βœ“ Correct Answer: (A) Saturday

Explanation:

  • Step 1: We know Jan 1, 2000 was Saturday.

  • Step 2: Calculate odd days from 2000 to 2049 (50 years).

  • Step 3: Leap years: 2000, 04, 08, 12, 16, 20, 24, 28, 32, 36, 40, 44, 48 = 13 leap years.

  • Step 4: Ordinary years = 50 - 13 = 37.

  • Step 5: Odd days = 13Γ—2 + 37Γ—1 = 26 + 37 = 63.

  • Step 6: 63 Γ· 7 = 9 weeks + 0 odd days.

  • Step 7: Saturday + 0 = Saturday


Q20. If 6th March, 2005 was Sunday, what was the day on 6th March, 1999?

(A) Monday    (B) Saturday    (C) Sunday    (D) Tuesday

βœ“ Correct Answer: (B) Saturday

Explanation:

  • Step 1: From 6th March 1999 to 6th March 2005 = 6 years.

  • Step 2: Leap years in between: 2000, 2004 = 2 leap years.

  • Step 3: Ordinary years = 4.

  • Step 4: Odd days = 2Γ—2 + 4Γ—1 = 4 + 4 = 8 = 1 odd day.

  • Step 5: If 1999 date + 1 odd day = Sunday (2005 date).

  • Step 6: Then 1999 date = Sunday - 1 = Saturday


πŸ“Š Answer Key

Q.No

Answer

Q.No

Answer

Q.No

Answer

Q.No

Answer

1

C

6

A

11

B

16

B

2

B

7

C

12

B

17

C

3

B

8

B

13

C

18

B

4

B

9

B

14

A

19

A

5

A

10

B

15

B

20

B


πŸ“š Sub-Topics Covered

  1. Leap Year Identification - Q1, Q4

  2. Odd Days in Years - Q2, Q5, Q6

  3. Day After/Before Calculations - Q3, Q6, Q11, Q13

  4. Repeating Calendars - Q7, Q17

  5. Historical Dates - Q8, Q15

  6. Backward Day Calculation - Q9, Q18, Q20

  7. Frequency of Dates - Q10, Q14

  8. Century Calculations - Q12

  9. First/Last Day of Year - Q16

  10. Future Date Calculations - Q19


πŸ’‘ Key Formulas to Remember

Formula/Concept

Value

Odd days in ordinary year

1

Odd days in leap year

2

Odd days in 100 years

5

Odd days in 200 years

3

Odd days in 300 years

1

Odd days in 400 years

0

Leap year repeats calendar

Every 28 years

Ordinary year repeats calendar

Every 6 or 11 years


πŸ”‘ Quick Reference - Day Codes

Odd Days

Day of Week

0

Sunday

1

Monday

2

Tuesday

3

Wednesday

4

Thursday

5

Friday

6

Saturday


πŸ“… Month-wise Odd Days

Month

Days

Odd Days

January

31

3

February (Ordinary)

28

0

February (Leap)

29

1

March

31

3

April

30

2

May

31

3

June

30

2

July

31

3

August

31

3

September

30

2

October

31

3

November

30

2

December

31

3


🎯 Leap Year Rules

  1. Divisible by 4 β†’ Leap year (usually)

  2. Divisible by 100 β†’ NOT a leap year

  3. Divisible by 400 β†’ IS a leap year

Examples:

  • 2024 β†’ Leap (divisible by 4)

  • 1900 β†’ NOT Leap (divisible by 100, not by 400)

  • 2000 β†’ Leap (divisible by 400)


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SSC CGL Reasoning Calendar MCQ Calendar Reasoning Questions SSC CGL Tier 1 Preparation Reasoning Questions with Answers Odd Days Concept Leap Year Questions Finding Day of Week SSC CGL 2025 Logical Reasoning MCQ Government Exam Preparation Free SSC Study Material Calendar Aptitude Questions
Calendar Reasoning Questions for SSC CGL 2025: 20 Practice MCQs with Solutions | Odd Days, Leap Year & Day Finding